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If $(2,3,-3)$ is one end of a diameter of the sphere $x^2+y^2+z^2-6x-12y-2z+20=0$ then the other end of the diameter is :

\[\begin {array} {1 1} (1)\;(4,9,1) & \quad (2)\;(4,9,5) \\ (3)\;(-8,-15,1) & \quad (4)\;(8,15,5) \end {array}\]

1 Answer

(2) (4,9,5)
answered Nov 7, 2013 by pady_1
 

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