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$y= \cos ^{-1}\bigg[\large\frac{a^2-x^2}{a^2+x^2}\bigg]+ \sin ^{-1} \bigg[\large\frac{2ax}{a^2+x^2}\bigg]=>\frac{dy}{dx}=$

\[\begin {array} {1 1} (1)\;\frac{a}{x^2+a^2} & \quad (2)\;\frac{2a}{x^2+a^2} \\ (3)\;\frac{4a}{x^2+a^2} & \quad (4)\;\frac{a^2}{x^2+a^2} \end {array}\]

1 Answer

$ (3)\;\frac{4a}{x^2+a^2} $
answered Nov 7, 2013 by pady_1
 
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