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$ y= \sin (m \sin ^{-1} x) =>(1-x^2)y_2-xy_1= $ (Here $y_n$ denotes $\large\frac{d^ny}{dx^n}$)

\[\begin {array} {1 1} (1)\;m^2y & \quad (2)\;-m^2y \\ (3)\;2m^2y & \quad (4)\;-2m^2y \end {array}\]

1 Answer

(2) $-m^2y$
answered Nov 7, 2013 by pady_1
 
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