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The area ( in square units) of the region enclosed by the two circles $x^2+y^2=1$ and $(x-1)^2+y^2=1$ is :

\[\begin {array} {1 1} (1)\;\frac{2\pi}{3}+\frac{\sqrt 3}{2} & \quad (2)\;\frac{\pi}{3} +\frac{\sqrt 3}{2}\\ (3)\;\frac{\pi}{3}-\frac{\sqrt 3}{2} & \quad (4)\;\frac{2 \pi}{3}-\frac{\sqrt 3}{2} \end {array}\]
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1 Answer

$ (4)\;\frac{2 \pi}{3}-\frac{\sqrt 3}{2}$
answered Nov 7, 2013 by pady_1
 

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