Ask Questions, Get Answers
Menu
X
JEEMAIN Crash Practice
15 Test Series
NEET Crash Practice
5 Test Series
CBSE XII
Math
JEEMAIN
Math
Physics
Chemistry
Practice Test Series
CBSE XI
Math
NEET
Physics
Chemistry
Biology - XII
Biology - XI
Olympiad class V
Math - 5 Test Series
Olympiad class VI
Math - 5 Test Series
studyplans
JEEMAIN Crash Practice
15 Test Series
NEET Crash Practice
5 Test Series
CBSE XII
Math
JEEMAIN
Math
Physics
Chemistry
Practice Test Series
CBSE XI
Math
NEET
Physics
Chemistry
Biology - XII
Biology - XI
Olympiad class V
Math - 5 Test Series
Olympiad class VI
Math - 5 Test Series
mobile
exams
ask
sample papers
teach
pricing
sign-in
Download our FREE mobile app with 1000+ tests for CBSE, JEE MAIN, NEET
X
Search
Topics
Want to ask us a question?
Click here
Browse Questions
Student Questions
Ad
Home
>>
EAMCET
>>
Mathematics
0
votes
The area ( in square units) of the region enclosed by the two circles $x^2+y^2=1$ and $(x-1)^2+y^2=1$ is :
\[\begin {array} {1 1} (1)\;\frac{2\pi}{3}+\frac{\sqrt 3}{2} & \quad (2)\;\frac{\pi}{3} +\frac{\sqrt 3}{2}\\ (3)\;\frac{\pi}{3}-\frac{\sqrt 3}{2} & \quad (4)\;\frac{2 \pi}{3}-\frac{\sqrt 3}{2} \end {array}\]
jeemain
eamcet
math
2010
q77
Share
asked
Sep 29, 2013
by
meena.p
Please
log in
or
register
to add a comment.
Can you answer this question?
Do not ask me again to answer questions
Please
log in
or
register
to answer this question.
1 Answer
0
votes
$ (4)\;\frac{2 \pi}{3}-\frac{\sqrt 3}{2}$
answered
Nov 7, 2013
by
pady_1
Please
log in
or
register
to add a comment.
Related questions
0
votes
0
answers
The line $x= \large\frac{\pi}{4}$ divides the area of the region bounded by $y=\sin x, y= \cos x$ and x-axis $\bigg(0 \leq x \leq \large\frac{\pi}{2}\bigg)$ into two regions of areas $A_1$ and $A_2$. Then $A_1 : A_2=$
asked
Oct 10, 2013
by
meena.p
jeemain
eamcet
math
2009
q77
0
votes
1
answer
The area (in square units) bounded by the curves $x=-2y^2$ and $x=1-3y^2$ is
asked
Sep 17, 2013
by
meena.p
jeemain
eamcet
math
2013
q77
0
votes
1
answer
The area (in square units) of the region bounded by the curves $2x=y^2-1$ and $x=0$ is
asked
Oct 18, 2013
by
meena.p
jeemain
eamcet
math
2008
q76
0
votes
1
answer
The values of a function $f(x)$ at different values of x are as follows: $x : \; 0\; 1\; 2\; 3\; 4\; 5\; \qquad f(x):\; 2\; 3 \; 6\; 11\; 18\; 27$ Then the approximate area (in square units) bounded by the curve $y=f(x)$ and X-axis between $x=0$ and 5, using Trapezoidal rule, is :
asked
Sep 29, 2013
by
meena.p
jeemain
eamcet
math
2010
q78
0
votes
1
answer
If a straight line L is perpendicular to the line $4x-2y=1$ and forms a triangle of area 4 square units with the coordinate axes, then an equation of the line L is :
asked
Sep 27, 2013
by
meena.p
jeemain
eamcet
math
2010
q42
0
votes
1
answer
The area (in square units) of the region bounded by the curves $x=y^2$ and $x=3-2y^2$ is
asked
Sep 20, 2013
by
meena.p
jeemain
eamcet
math
2011
q14
0
votes
1
answer
The area (in square unit ) of the region enclosed by the curves $ y=x^2$ and $y=x^3$ is
asked
Oct 28, 2013
by
meena.p
jeemain
eamcet
math
2007
q76
Ask Question
SUBMIT QUESTION
►
Please Wait
Take Test
JEEMAIN Crash Practice
15 Test Series
NEET Crash Practice
5 Test Series
JEEMAIN
350+ TESTS
NEET
320+ TESTS
CBSE XI MATH
50+ TESTS
CBSE XII MATH
80+ TESTS
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...