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If the force is given by $F= at +bt^2$ with t as time. The dimensions of a and b are :

\[\begin {array} {1 1} (1)\;MLT^{-4},MLT^{-2} & \quad (2)\;MLT^{-3},MLT^{-4} \\ (3)\;ML^2T^3,ML^2T^{-2} & \quad (4)\;ML^2T^{-3},ML^{3}T^{-4} \end {array}\]
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$(2)\;MLT^{-3},MLT^{-4} $
answered Nov 7, 2013 by pady_1

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