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Physics
The moment of inertia of a disc, of mass M and radius R, about an axis which is a tangent and to its diameter is :
\[\begin {array} {1 1} (1)\;\frac{1}{2} MR^2 & \quad (2)\;\frac{3}{4} MR^2 \\ (3)\;\frac{1}{4}MR^2 & \quad (4)\;\frac{5}{4}MR^2 \end {array}\]
jeemain
eamcet
physics
2010
q89
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asked
Sep 30, 2013
by
meena.p
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$ (4)\;\frac{5}{4}MR^2 $
answered
Nov 7, 2013
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pady_1
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