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The displacements of two particles of same mass executing $SHM$ are represented by the equations $x_1=4 \sin \bigg[10t+\large\frac{\pi}{6}\bigg]$ and $x_2=5 \; \cos(\omega t)$. The value of $\omega$ for which the energy of both the particles remain same is :

\[\begin {array} {1 1} (1)\;16\;units & \quad (2)\;6\;units \\ (3)\;4\;units & \quad (4)\;8\;units \end {array}\]

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1 Answer

(4) 8 units
answered Nov 7, 2013 by pady_1
 

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