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The distance between field lens and eye lens in Ramsden eyepiece is $4 cm$. Then, the distance of the cross-wires from the eye lens is :

\[\begin {array} {1 1} (1)\;1.5 \;cm & \quad (2)\;1.0\;cm \\ (3)\;5.0\;cm & \quad (4)\;5.5\;cm \end {array}\]
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(4) 5.5 cm
answered Nov 7, 2013 by pady_1

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