Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  EAMCET  >>  Physics
0 votes

In Thomson's experiment to determine $\large\frac{e}{m}$ of an electron , it is found that an electron beam having a kinetic energy of $45.5\;eV$ remains undeflected, when subjected to crossed electric and magnetic fields. If $E=1 \times 10^{3} Vm^{-1}$, the value of $'B'$ is (mass of the electron is $9.1 \times 10^{-31}\;kg$) :

\[\begin {array} {1 1} (1)\;2.5 \times 10^{-3} \;Wb m^{-2} & \quad (2)\;5.0 \times 10^{-4} \;Wb m^{-2} \\ (3)\;2.5 \times 10^{-4} \;Wb m^{-2} & \quad (4)\;1.0 \times 10^{-4} \;Wb m^{-2} \end {array}\]
Can you answer this question?

Please log in or register to answer this question.

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App