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# $CH_4$ diffuses two times faster than a gas X. The number of molecules present in 32 g of gas X is : (N is Avogadro number)

$\begin {array} {1 1} (1)\;N & \quad (2)\;\frac{N}{2} \\ (3)\;\frac{N}{4} & \quad (4)\;\frac{N}{16} \end {array}$
Can you answer this question?

$(2)\;\frac{N}{2}$
answered Nov 7, 2013 by