\[\begin {array} {1 1} (a)\;60\;mm & \quad (b)\;40\;mm \\ (c)\;30\;mm & \quad (d)\;10\;mm \end {array}\]

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We know the height of the capillary rise.

$h=\large\frac{2 T \cos \theta}{rdg}$

$T$- surface tension

$r$- radius

$d$- density

$g$ - acceleration due to gravity

$h_1r_1=h_2r_2$

$\therefore \large\frac{h_2}{h_1}=\frac{r_1}{r_2}$

$\qquad=\frac{1}{\bigg(\Large\frac{1}{3}\bigg)}$

$\qquad =3$

$h_2= 3 \times h_1$

$\quad= 3 \times 20$

$\quad=60 \; mm$

Hence a is the correct answer.

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