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Q)

What is the work done in splitting a drop of water 1 mm radius into $10^6$ droplets (surface tension of water $= 72 \times 10^{-3} \; J/m^2$)

\[\begin {array} {1 1} (a)\;8.95 \times 10^{-5}\;J \\ (b)\;2.45 \times 10^{-5}\;J \\ (c)\;3.25 \times 10^{-4}\;J \\ (d)\;2.10 \times 10^{-4}\;J \end {array}\]

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