Want to ask us a question? Click here

Browse Questions

Ad |

0 votes

\[\begin {array} {1 1} (a)\;7.2 \times 10^{-7} \\ (b)\;15.2 \times 10^{-7} \\ (c)\;8.4 \times 10^{-7} \\ (d)\;12.1 \times 10^{-7} \end {array}\]

0 votes

$Mass= 50000\;kg$

Area of cross section of 4 cylindrical column

$A=4 \pi (0.6^2-0.3^2)$

$Y= 2.0 \times 10^{11} Nm^{-2}$

$Y=\large\frac{MgL}{A \Delta L}$

$\large\frac{\Delta L}{L}=\frac{Mg}{AY}$

$\qquad= \large\frac{50,000 \times 9.8}{4 \times 3.14 \times (0.6^2 -0.3)^2) \times 2 \times 10^{11}}$

$\qquad= 7.2 \times 10^{-7}$

Hence a is the correct answer.

Ask Question

Tag:MathPhyChemBioOther

Take Test

x

JEE MAIN, CBSE, NEET Mobile and Tablet App

The ultimate mobile app to help you crack your examinations

...