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# A volume of 10 ml of gaseous c4Hx exactly requires 55 ml of oxygen for comp

A volume of 10 ml of gaseous c4Hx exactly requires 55 ml of oxygen for complete combustion.find value of x

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A)
$C_4H_X + (4+\frac{X}{4})O_2 \rightarrow 4CO_2 + \frac{X}{2} H_2O$

combustion of 1 volume $C_4H_X$ with $(4 + \frac{X}{4})$ volumes $O_2$ give 4 volumes $CO_2 + \frac{X}{2}$ volumes $H_2O$

$\frac{10}{1} = \frac{55}{(4+\frac{X}{4})}$

$\therefore 10(4 +\frac{X}{4}) = 55$

$\therefore 40 + \frac{10X}{4} = 55$

$\therefore \frac{10X}{4} = 55-40$

$\therefore \frac{10X}{4} = 15$

$\therefore 10X = 60$

Hence X = 6