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A wire breaks when subjected to a stress S. If $\rho$ is the density of the material of wire, then the length of the wire. So that it breaks by its own weight is

\[\begin {array} {1 1} (a)\;\rho\;g\;s \\ (b)\;\frac{\rho\;g}{s} \\ (c)\;\frac{gs}{\rho} \\ (d)\;\frac{s}{\rho\;g} \end {array}\]<

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1 Answer

Let $L$ be length of the wire stress due to the length $L= L \rho g$
$s= L \rho g$
$\therefore L=\large\frac{s}{\rho g}$
Hence d is the correct answer. 


answered Oct 3, 2013 by meena.p
edited Feb 18, 2014 by meena.p

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