# A wire breaks when subjected to a stress S. If $\rho$ is the density of the material of wire, then the length of the wire. So that it breaks by its own weight is

$\begin {array} {1 1} (a)\;\rho\;g\;s \\ (b)\;\frac{\rho\;g}{s} \\ (c)\;\frac{gs}{\rho} \\ (d)\;\frac{s}{\rho\;g} \end {array}$<

Let $L$ be length of the wire stress due to the length $L= L \rho g$
$s= L \rho g$
$\therefore L=\large\frac{s}{\rho g}$
Hence d is the correct answer.

edited Feb 18, 2014 by meena.p