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The bulk modulus of elasticity of helium at 1 atmospheric pressure, assuming variation of pressure and volume is adiabatic, is

\[\begin {array} {1 1} (a)\;7.31 \times 10^5\;Pa \\ (b)\;1.73 \times 10^5 \;Pa \\ (c)\;2.5 \times 10^4\;Pa \\ (d)\;5.73 \times 10^7 \;Pa \end {array}\]
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Back modulus for adiabatic process $=rp$
$r$ for lelium $=\large\frac{5}{3}$
$1$ atmosphere $=1.01 \times 10^5 \;pa$
$\therefore $ Bulk modulus $=\large\frac{5}{3} $$ \times 1.01 \times 10^5$
$\qquad=1.73 \times 10^5$
Hence b is the correct answer. 


answered Oct 3, 2013 by meena.p
edited Feb 18, 2014 by meena.p

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