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An oxide of sulphur contains 50%S what will be its empirical formula

An oxide of sulphur contains 50%S what will be its empirical formula

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A)
Element  Percentage Atomic Mass Moles Ratio of the moles
S 50 32.07 50/37.07 = 1.55 1.55/1.55 = 1
O 50 16 50/16 = 3.125 3.125/1.55 = 2

Therefore, the empirical formula of the compound is $S_1O_2$ or $SO_2$

 

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