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what is the mole fraction of benzene and toluene when 117 grams of benzene

what is the mole fraction of benzene and toluene when 117 grams of benzene mixed with 46 grams of tollune

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Refer:

Number of moles of benzene = 117 / 78 = 1.5 mol

Number of mole of toluene = 46 / 9 2 = 0.5  mol

Mole fraction of benzene, $X_{Benzene}$ = 1.5 / (1.5 + 0.5)  = 1.5/ 2 = 0.75

Mole fraction of toluene, $X_{ Toluene}$ = $1 – X_{Benzene}$ = 1 – 0.75 = 0.25

 

 

 
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