Email
Chat with tutor
logo

Ask Questions, Get Answers

X
 
Answer
Comment
Share
Q)

A capillary of shapes as shown is dipped in a liquid. Contact angle between liquid minisues is to be neglected . T is surface tension of liquid, r is radius of meniscus g is acceleration due to gravity $\rho$ is density of the liquid then height h in equillibrium is

$\begin{array}{1 1} a) greater\; then \;\large\frac{2T}{r \rho g} \\ b) equal \;to \large\frac{2T}{r \rho g} \\ c) less \;than \;\large\frac{2T}{r \rho g} \\ d) \text{any value depending actual value of T} \end{array}$

1 Answer

Comment
A)
As weight of liquid in capillary is balanced by surface tension then $T \times 2 \pi r= \pi r^2 h_1 \rho g$
$h_1= \large\frac{2T}{r\rho g}$
But weight of liquid in tapered table as shown is more than uniform tube of radius the r then in order to balance the weight $h < h_1$
$\therefore h < \large\frac{2T}{r \rho g}$
Hence c is the correct answer.

 

Help Clay6 to be free
Clay6 needs your help to survive. We have roughly 7 lakh students visiting us monthly. We want to keep our services free and improve with prompt help and advanced solutions by adding more teachers and infrastructure.

A small donation from you will help us reach that goal faster. Talk to your parents, teachers and school and spread the word about clay6. You can pay online or send a cheque.

Thanks for your support.
Continue
Please choose your payment mode to continue
Home Ask Homework Questions
Your payment for is successful.
Continue
Clay6 tutors use Telegram* chat app to help students with their questions and doubts.
Do you have the Telegram chat app installed?
Already installed Install now
*Telegram is a chat app like WhatsApp / Facebook Messenger / Skype.
...