\[\begin {array} {1 1} (a)\;Mg (1-\frac{d_2}{d_1}) \\ (b)\; Mg(1+\frac{d_2}{d_1}) \\ (c)\;2Mg (1-\frac{d_2}{d_1}) \\ (d)\;none\;of\;these \end {array}\]

Since the ball attains equilibrium when the velocity becomes constant.

The effective force of the liquid must balance the viscous force

Effective force $= V (d_1 -d_2)g$

But $v=\large\frac{M}{d_1}$

$\therefore$ effective viscous force $= \large\frac{M}{d_1}$$(d_1-d_2)g$

$ \qquad= Mg (1- \large\frac{d_2}{d_1})$

Hence a is the correct answer.

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