Upthrust in the cylinder
$\qquad= \bigg(\large\frac{m}{\rho}\bigg)$$ \sigma g$
[when $\large\frac{m}{\rho}$$=V$] Volume of cylinder
From's Newton's third law force. exerted by the cylinder on the liquid is also $\bigg(\large\frac{m}{\rho}\bigg)$$ \sigma g$
$\therefore $ Increase in pressure $=\large\frac{Force}{area}$
$\qquad= \large\frac{\Large\frac{m}{\rho}\sigma g}{s}$
$\qquad= \large\frac{m \sigma g}{\rho s}$
Hence c is the correct answer.