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Two liquids which do not react chemically are placed in a bent tube as shown. The heights of liquids above their surface of separation (Common surface) are

a) directly proportional to their densities
b) inversely proportional to their densities
c) directly proportional to square of their densities
d) equal

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Pressure at the interface of two liquids must be same, calculated via either of the two limbs of the U tube.
$h_0 \rho _1 g =h_2 \rho_2 g$
$h_1 \rho_1=h_2 \rho_2$
$h \rho=constant$
$\therefore\; h \alpha \large\frac{1}{\rho}$
Hence b is the correct answer.


answered Oct 8, 2013 by meena.p
edited Feb 18, 2014 by meena.p

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