Email
Chat with tutor
logo

Ask Questions, Get Answers

X
 
Answer
Comment
Share
Q)

A wooden cube is floating in water when a mass $m= 0.2\;kg$ is kept on its top, When the mass is removed the cube rises by $2 \;cm$. The side of the cube is [density of water $=10^3 kg/m^3$]

\[\begin {array} {1 1} (a)\;6\;cm \\ (b)\;12\;cm \\ (c)\;10\;cm \\ (d)\;8\;cm \end {array}\]

1 Answer

Comment
A)
Since the cube rise by 2cm there is a decrease in upthrust due to the decrease in weight.
Volume of water $=V=2 \times 10^{-2} \times Area\; of\; base$
upthrust $=V \rho _w g= 2 \times 10^{-2} \times A \times10^3 \times g$
$\therefore mg = 2 \times 10^{-2} \times A \times 10^3 \times g$
$0.2= 2 \times 10^{-2} \times 10^3 \times A$
$A=10^{-2}\;m^2$
$\therefore$ Side of the cube $=10\;cm$
Hence c is the correct answer.

 

Help Clay6 to be free
Clay6 needs your help to survive. We have roughly 7 lakh students visiting us monthly. We want to keep our services free and improve with prompt help and advanced solutions by adding more teachers and infrastructure.

A small donation from you will help us reach that goal faster. Talk to your parents, teachers and school and spread the word about clay6. You can pay online or send a cheque.

Thanks for your support.
Continue
Please choose your payment mode to continue
Home Ask Homework Questions
Your payment for is successful.
Continue
Clay6 tutors use Telegram* chat app to help students with their questions and doubts.
Do you have the Telegram chat app installed?
Already installed Install now
*Telegram is a chat app like WhatsApp / Facebook Messenger / Skype.
...