\[\begin {array} {1 1} (a)\;6\;cm \\ (b)\;12\;cm \\ (c)\;10\;cm \\ (d)\;8\;cm \end {array}\]

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Since the cube rise by 2cm there is a decrease in upthrust due to the decrease in weight.

Volume of water $=V=2 \times 10^{-2} \times Area\; of\; base$

upthrust $=V \rho _w g= 2 \times 10^{-2} \times A \times10^3 \times g$

$\therefore mg = 2 \times 10^{-2} \times A \times 10^3 \times g$

$0.2= 2 \times 10^{-2} \times 10^3 \times A$

$A=10^{-2}\;m^2$

$\therefore$ Side of the cube $=10\;cm$

Hence c is the correct answer.

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