Email
Chat with tutor
logo

Ask Questions, Get Answers

X
 
Answer
Comment
Share
Q)

Power required to raise $300 liters$ of water per minute through a height of 6m using a pipe of diameter 2.4 cm is $(g=10 m/s^2)$

\[\begin {array} {1 1} (a)\;600\;walt \\ (b)\;400\;walt \\ (c)\;1000\;walt \\ (d)\;2000\;walt \end {array}\]

1 Answer

Comment
A)
$W_1$= Work done against gravity $=mgh$
$ \qquad=V \rho gh$
Work done against pressure difference
$W_2=\Delta PV= h \rho gV$
Total work done $=W_1 +W_2$
$\qquad= 2h \rho gV$
$P= \large\frac{W}{t}$
$\quad= \large\frac{2 \times 6 \times 10^3 \times 10 \times 300 \times 10^{-3}}{60}$
$\quad= 600\; walt$
Hence a is the correct answer.

 

Help Clay6 to be free
Clay6 needs your help to survive. We have roughly 7 lakh students visiting us monthly. We want to keep our services free and improve with prompt help and advanced solutions by adding more teachers and infrastructure.

A small donation from you will help us reach that goal faster. Talk to your parents, teachers and school and spread the word about clay6. You can pay online or send a cheque.

Thanks for your support.
Continue
Please choose your payment mode to continue
Home Ask Homework Questions
Your payment for is successful.
Continue
Clay6 tutors use Telegram* chat app to help students with their questions and doubts.
Do you have the Telegram chat app installed?
Already installed Install now
*Telegram is a chat app like WhatsApp / Facebook Messenger / Skype.
...