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The minimum value of $\cos(\cos x)$ is

$(a)\;0\qquad(b)\;-\cos 1\qquad(c)\;\cos 1\qquad(d)\;-1$

1 Answer

$\cos x$ varies from $-1$ to $1$ for all real $x$.
Thus $\cos(\cos x)$ varies from $\cos 1$ to $\cos 0$
$\Rightarrow $ Minimum value of $\cos (\cos x)$ is $\cos 1$.
Hence (c) is the correct answer.
answered Oct 7, 2013 by sreemathi.v
 

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