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Home  >>  JEEMAIN and AIPMT  >>  Mathematics  >>  Trignometry
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In $\sin x=-\cos^2x$ then $\cos^2x(1+\cos^2x)$ equals

$(a)\;0\qquad(b)\;1\qquad(c)\;2\qquad(d)\;None\;of\;these$

Can you answer this question?
 
 

1 Answer

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$\cos^2x(1+\cos^2x)=\cos^2x+\cos^4x$
$\qquad\qquad\qquad\quad=\cos^2x+\sin^2x$
$\cos^2x+\sin^2x=1$
$\qquad\qquad\qquad\quad=1$
Hence (b) is the correct answer.
answered Oct 7, 2013 by sreemathi.v
 

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