Browse Questions

# If in a $\Delta ABC$ $\angle C=90^{\circ}$ then the maximum value of $\sin A\sin B$ is

$(a)\;\large\frac{1}{2}$$\qquad(b)\;1\qquad(c)\;2\qquad(d)\;None\;of\;these Can you answer this question? ## 1 Answer 0 votes \sin A\sin B=\large\frac{1}{2}$$\times 2\sin A\sin B$
$\qquad\quad\quad\;=\large\frac{1}{2}$$[\cos(A-B)-\cos(A+B)] \qquad\quad\quad\;=\large\frac{1}{2}$$[\cos(A-B)-\cos 90^{\circ}]$