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Questions  >>  CBSE XI  >>  Chemistry  >>  Structure of Atom
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calculate the Broglie wavelength of an electron moving with 1% of the speed of light ?

$\begin{array}{1 1} (a)\;2.43 \times 10^{-10} \;m \\(b)\;3.43 \times 10^{-10} \;m\\ (c)\;4.43 \times 10^{-10} \;m\\ (d)\;5.43 \times 10^{-10} \;m\end{array} $

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A)
Solution :
According to be Broglie equation $\lambda=\large\frac{h}{mv}$
Mass of electron $=9.1 \times 10^{-31}\;kg$
Planck's constant $=6.626 \times 10^{-34}\;kgm^2s^{-1}$
Velocity of electron $(\lambda)=\large\frac{h}{mv}$
$\qquad= \large\frac{(6.626 \times 10^{-34}kg m^2s^{-1})}{(9.1 \times 10^{-31}\;kg)\times (3 \times 10^6ms^{-1})}$
$\qquad= 2.43 \times 10^{-10}\;m$
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