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Questions  >>  CBSE XI  >>  Chemistry  >>  Structure of Atom
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Q)

Calculate the accelerating potential that must be applied to a proton beam to give it an effective wavelength of 0.005 nm.

$\begin{array}{1 1} (a)\;32.85\;volt \\(b)\;42.85\;volt\\ (c)\;52.85\;volt\\ (d)\;62.85\;volt\end{array} $

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A)
Solution:
$v= \large\frac{h}{m \lambda}$
$ev=\large\frac{1}{2mv^2}$
Putting the values we get,
$V= 32.85\;volt$
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