Email
Chat with tutor
logo

Ask Questions, Get Answers

X
 
Questions  >>  CBSE XI  >>  Chemistry  >>  Structure of Atom
Answer
Comment
Share
Q)

Calculate the ratio of K.E and P.E of an electron in an orbit?

$\begin{array}{1 1} (a)\;\frac{-1}{2} \\(b)\;\frac{-3}{2}\\ (c)\;\frac{-4}{2}\\ (d)\;\frac{-5}{2}\end{array} $

1 Answer

Comment
A)
Solution :
$K.E=\large\frac{Ze^2}{2r}$
$P.E=\large\frac{-Ze^2}{2r}$
$\therefore P.E=-2K.E$
$\therefore K.E/P.E=\large\frac{-1}{2}$
Help Clay6 to be free
Clay6 needs your help to survive. We have roughly 7 lakh students visiting us monthly. We want to keep our services free and improve with prompt help and advanced solutions by adding more teachers and infrastructure.

A small donation from you will help us reach that goal faster. Talk to your parents, teachers and school and spread the word about clay6. You can pay online or send a cheque.

Thanks for your support.
Continue
Please choose your payment mode to continue
Home Ask Homework Questions
Your payment for is successful.
Continue
Clay6 tutors use Telegram* chat app to help students with their questions and doubts.
Do you have the Telegram chat app installed?
Already installed Install now
*Telegram is a chat app like WhatsApp / Facebook Messenger / Skype.
...