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Q)

Calculate the ratio of K.E and P.E of an electron in an orbit?

$\begin{array}{1 1} (a)\;\frac{-1}{2} \\(b)\;\frac{-3}{2}\\ (c)\;\frac{-4}{2}\\ (d)\;\frac{-5}{2}\end{array}$

$K.E=\large\frac{Ze^2}{2r}$
$P.E=\large\frac{-Ze^2}{2r}$
$\therefore P.E=-2K.E$
$\therefore K.E/P.E=\large\frac{-1}{2}$