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Questions  >>  CBSE XII  >>  Math  >>  Matrices
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Q)

The number of all possible matrices of order 3 x 3 with each entry 0 or 1 is:

$\begin{array}{1 1} 27 \\ 18 \\ 81 \\ 512 \end{array} $

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A)
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  • There are 9 elements in $3\times 3$ matrix and one element can be filled in two ways either 0 or 1.
$\Rightarrow$ Total possible matrices =$2^9$=512.
 
Ans:(D).

 

 
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The number of elements in a $3$ X $3$ matrix is the product $3$ X $3 = 9$.
Each element can either be a 0 or a 1.
Given this, the total possible matrices that can be selected is $2^9 = 512$.
Hence, the solution is $(D): 512$.
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