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The magnifying power of the astronomical telescope for normal adjustment is 50. The focal length of the eye piece is 2cm. The required length of the telescope for normal adjustment is

$\begin {array} {1 1} (1)\;102\: cm & \quad (2)\;100\: cm \\ (3)\;98\: cm & \quad (4)\;25\: cm \end {array}$

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(1) 102 cm
answered Nov 7, 2013 by pady_1
 

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