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The roots of $(x-a)(x-a-1)+(x-a-1)(x-a-2)+(x-a)(x-a-2)=0,a \in R$ are always:

(1) equal

(2) imaginary

(3) real and distinct

(4) rational and equal

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1 Answer

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(3) real and distinct
answered Nov 7, 2013 by pady_1

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