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If $cosec A+\cot A=\large\frac{11}{2}$ then $\tan A$ is

$(a)\;\large\frac{21}{22}\qquad$$(b)\;\large\frac{15}{16}$$\qquad(c)\;\large\frac{44}{117}$$\qquad(d)\;\large\frac{117}{43}$

1 Answer

$cosec A+\cot A=\large\frac{11}{2}$
$cosec^2A-\cot^2A=1$
$\Rightarrow cosec A-\cot A=\large\frac{2}{11}$
$\Rightarrow 2\cot A=\large\frac{177}{2}$
$\tan A=\large\frac{44}{117}$
Hence (c) is the correct option.
answered Oct 9, 2013 by sreemathi.v
 

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