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Q)

If $\tan\alpha=\large\frac{x}{x+1}$ and $\tan \beta=\large\frac{1}{2x+1}$ then $\alpha+\beta$ is

$(a)\;0\qquad(b)\;\large\frac{\pi}{4}$$\qquad(c)\;\large\frac{\pi}{3}$$\qquad(d)\;\large\frac{\pi}{2}$

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