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In a $\Delta ABC \; \large\frac{(a+b+c)(b+c-a)(c+a-b)(a+b-c)}{4b^2c^2}$$=$

\[\begin {array} {1 1} (1)\;\cos^2 A & \quad (2)\;\cos^2 B \\ (3)\;\sin^2 A & \quad (4)\;\sin^2 B \end {array}\]

1 Answer

(3) $\sin^2 A$
answered Nov 7, 2013 by pady_1
 

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