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In a quadrilateral $ABCD,$ the point P divides DC in the ratio $1:2$ and Q is the mid point of AC.If $\overrightarrow {AB}+2 \overrightarrow {AD}+\overrightarrow {BC}-2 \overrightarrow {DC}=k \overrightarrow {PQ}$, then $k= $

\[\begin {array} {1 1} (1)\;-6 & \quad (2)\;-4 \\ (3)\;6 & \quad (4)\;4 \end {array}\]

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(1) -6
answered Nov 7, 2013 by pady_1

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