logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
Home  >>  EAMCET  >>  Physics
0 votes

In the equation $ \bigg( \large\frac{1}{P \beta} \bigg)= \large\frac{y}{k_BT}$, where P is the pressure, y is the distance, $k_B$ is Boltzmann constant and T is the temperature. Dimensions of $ \beta $ are

$\begin {array} {1 1} (1)\;M^{-1}L^1T^2 & \quad (2)\;M^0L^2T^0 \\ (3)\;M^1L^{-1}T^{-2} & \quad (4)\;M^0L^0T^0 \end {array}$

 

Can you answer this question?
 
 

1 Answer

0 votes
(2) $M^0L^2T^0$
answered Nov 7, 2013 by pady_1
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...