Ask Questions, Get Answers

Home  >>  EAMCET  >>  Physics

A ball of mass 'm' moving with a horizontal velocity 'v' strikes the bob of a pendulum at rest. Mass of the bob of the pendulum is also 'm''. During this collision the ball sticks with the bob of the pendulum. The height to which the combined mass rises ( g = acceleration due to gravity )

$\begin {array} {1 1} (1)\;\large\frac{v^2}{4g} & \quad (2)\;\large\frac{v^2}{8g} \\ (3)\;\large\frac{v^2}{g} & \quad (4)\;\large\frac{v^2}{2g} \end {array}$

Download clay6 mobile app

1 Answer

(2) $ \large\frac{v^2}{8g}$
answered Nov 7, 2013 by pady_1

Related questions