logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
Home  >>  EAMCET  >>  Physics
0 votes

A ball of mass 'm' moving with a horizontal velocity 'v' strikes the bob of a pendulum at rest. Mass of the bob of the pendulum is also 'm''. During this collision the ball sticks with the bob of the pendulum. The height to which the combined mass rises ( g = acceleration due to gravity )

$\begin {array} {1 1} (1)\;\large\frac{v^2}{4g} & \quad (2)\;\large\frac{v^2}{8g} \\ (3)\;\large\frac{v^2}{g} & \quad (4)\;\large\frac{v^2}{2g} \end {array}$

Can you answer this question?
 
 

1 Answer

0 votes
(2) $ \large\frac{v^2}{8g}$
answered Nov 7, 2013 by pady_1
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...