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EAMCET
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Mathematics
The transformed equation of $x^2+y^2=r^2$ when the axes are rotated through an angle $36^{\circ}$ is :
\[\begin {array} {1 1} (1)\;\sqrt 5X^2-4XY+Y^2=r^2 & \quad (2)\;X^2+2XY-\sqrt 5 Y^2=r^2 \\ (3)\;X^2-Y^2=r^2 & \quad (4)\;X^2+Y^2=r^2 \end {array}\]
jeemain
eamcet
math
2009
q42
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asked
Oct 10, 2013
by
meena.p
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