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Home  >>  EAMCET  >>  Mathematics
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The points on the line $3x+4y=5$ which is equidistant from (1,2) and (3,4) is :

\[\begin {array} {1 1} (1)\;(7,-4) & \quad (2)\;(15,-10) \\ (3)\;(1/7,8/7) & \quad (4)\;(0,5/4) \end {array}\]
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(2) (15,-10)
answered Nov 7, 2013 by pady_1
 

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