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Home  >>  EAMCET  >>  Mathematics

The equation of the straight line perpendicular to the straight line $3x+2y=0$ and passing through the point of intersection of the lines $x+3y-1=0$ and $x-2y+4=0$ is :

\[\begin {array} {1 1} (1)\;2x-3y+1=0 & \quad (2)\;2x-3y+3=0 \\ (3)\;2x-3y+5=0 & \quad (4)\;2x-3y+7=0 \end {array}\]

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(4) 2x-3y+7=0
answered Nov 7, 2013 by pady_1
 

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