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The equation of the straight line perpendicular to the straight line $3x+2y=0$ and passing through the point of intersection of the lines $x+3y-1=0$ and $x-2y+4=0$ is :
\[\begin {array} {1 1} (1)\;2x-3y+1=0 & \quad (2)\;2x-3y+3=0 \\ (3)\;2x-3y+5=0 & \quad (4)\;2x-3y+7=0 \end {array}\]
jeemain
eamcet
math
2009
q45
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asked
Oct 10, 2013
by
meena.p
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1 Answer
(4) 2x-3y+7=0
answered
Nov 7, 2013
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pady_1
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