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The locus of center of a circle which passes through the origin and cuts off a length of 4 units from the line $x=3$ is :
\[\begin {array} {1 1} (1)\;y^2+6x=0 & \quad (2)\;y^2+6x=13 \\ (3)\;y^2+6x=10 & \quad (4)\;x^2+6y=13 \end {array}\]
jeemain
eamcet
math
2009
q50
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Oct 10, 2013
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meena.p
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$ (2)\;y^2+6x=13$
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Nov 7, 2013
by
pady_1
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