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EAMCET
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Mathematics
The locus of center of a circle which passes through the origin and cuts off a length of 4 units from the line $x=3$ is :
\[\begin {array} {1 1} (1)\;y^2+6x=0 & \quad (2)\;y^2+6x=13 \\ (3)\;y^2+6x=10 & \quad (4)\;x^2+6y=13 \end {array}\]
jeemain
eamcet
math
2009
q50
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asked
Oct 10, 2013
by
meena.p
Plz send solution ..
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1 Answer
$ (2)\;y^2+6x=13$
answered
Nov 7, 2013
by
pady_1
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