info@clay6.com
+91-9566306857  (or)  +91-9176170648
logo

Ask Questions, Get Answers

X
 
Home  >>  EAMCET  >>  Mathematics

The locus of center of a circle which passes through the origin and cuts off a length of 4 units from the line $x=3$ is :

\[\begin {array} {1 1} (1)\;y^2+6x=0 & \quad (2)\;y^2+6x=13 \\ (3)\;y^2+6x=10 & \quad (4)\;x^2+6y=13 \end {array}\]
Plz send solution ..

1 Answer

$ (2)\;y^2+6x=13$
answered Nov 7, 2013 by pady_1
 
...
close