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# The locus of center of a circle which passes through the origin and cuts off a length of 4 units from the line $x=3$ is :

$\begin {array} {1 1} (1)\;y^2+6x=0 & \quad (2)\;y^2+6x=13 \\ (3)\;y^2+6x=10 & \quad (4)\;x^2+6y=13 \end {array}$
Can you answer this question?

$(2)\;y^2+6x=13$
answered Nov 7, 2013 by