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The equation of the circle which passes through the origin and cuts orthogonally each of the circles $x^2+y^2-6x+8=0$ and $x^2+y^2-2x-2y=7$ is :

\[\begin {array} {1 1} (1)\;3x^2+3y^2-8x-13 y=0 & \quad (2)\;3x^2+3y^2-8x+29y=0 \\ (3)\;3x^2+3y^2+8x+29 y=0 & \quad (4)\;3x^2+3y^2-8x-29 y=0 \end {array}\]

1 Answer

$(2)\;3x^2+3y^2-8x+29y=0$
answered Nov 7, 2013 by pady_1
 
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