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If the distance between the foci of an ellipse is 6 and the length of the minor axis is 8, then the eccentricity is :

\[\begin {array} {1 1} (1)\;\frac{1}{\sqrt 5} & \quad (2)\;\frac{1}{2} \\ (3)\;\frac{3}{5} & \quad (4)\;\frac{4}{5} \end {array}\]
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answered Nov 7, 2013 by pady_1

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