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The mid point of the chord $4x-3y=5$ of the hyperbola $2x^2-3y^2=12$ is :

\[\begin {array} {1 1} (1)\;\bigg(0,-\frac{5}{3}\bigg) & \quad (2)\;(2,1) \\ (3)\;\bigg(\frac{5}{4},0\bigg) & \quad (4)\;\bigg(\frac{11}{4},2 \bigg) \end {array}\]

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1 Answer

$(2)\;(2,1)$
answered Nov 7, 2013 by pady_1
 
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