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The eccentricity of the conic $\large\frac{5}{r}$$=2 + 3 \cos \theta+ 4 \sin \theta$ is :

\[\begin {array} {1 1} (1)\;\frac{1}{2} & \quad (2)\;1 \\ (3)\;\frac{3}{2} & \quad (4)\;\frac{5}{2} \end {array}\]

1 Answer

$ (4)\;\frac{5}{2} $
answered Nov 7, 2013 by pady_1
 
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