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Home  >>  JEEMAIN and AIPMT  >>  Mathematics  >>  Trignometry
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In a $\Delta$le ABC let $\angle C=\large\frac{\pi}{2}$ if $r$ is the radius and R is the circumference of the $\Delta$le ABC then $2(r+R)$ equals

$(a)\;c+a\qquad(b)\;a+b+c\qquad(c)\;a+b\qquad(d)\;b+c$

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1 Answer

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Given :
$\angle C=\large\frac{\pi}{2}$
$\large\frac{C}{\sin C}$$=2R$
$2R=C$
$r=(s-C)\tan\large\frac{C}{2}$
$\;\;=s-C$
$2r+2R=2s-2C+C$
$2(r+R)=a+b$
Hence (c) is the correct option.
answered Oct 10, 2013 by sreemathi.v
 

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