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The radius of the sphere $x^2+y^2+z^2=12 x +4y+3z$ is :

\[\begin {array} {1 1} (1)\;\frac{13}{2} & \quad (2)\;13 \\ (3)\;26 & \quad (4)\;52 \end {array}\]
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1 Answer

$ (1)\;\frac{13}{2} $
answered Nov 7, 2013 by pady_1
 

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