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The radius of the sphere $x^2+y^2+z^2=12 x +4y+3z$ is :
\[\begin {array} {1 1} (1)\;\frac{13}{2} & \quad (2)\;13 \\ (3)\;26 & \quad (4)\;52 \end {array}\]
jeemain
eamcet
math
2009
q62
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Oct 10, 2013
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meena.p
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$ (1)\;\frac{13}{2} $
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Nov 7, 2013
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pady_1
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