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$x= \large\frac{1-\sqrt y}{1+\sqrt y}=>\large\frac{dy}{dx}=$

\[\begin {array} {1 1} (1)\;\frac{4}{(x+1)^2} & \quad (2)\;\frac{4(x-1)}{(1+x)^3} \\ (3)\;\frac{x-1}{(1+x)^3} & \quad (4)\;\frac{4}{(x+1)^3} \end {array}\]

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